- #71
azizlwl
- 1,066
- 10
chikis said:For the second question, solve the equation:
2(2x+1)- 9(2x) + 4 = 0
I don't just know how to start dealing with the question. It is really a troubsome question.
2(2x+1)=22x×21
22x=(2x)2
chikis said:For the second question, solve the equation:
2(2x+1)- 9(2x) + 4 = 0
I don't just know how to start dealing with the question. It is really a troubsome question.
azizlwl said:2(2x+1)=22x×21
22x=(2x)2
azizlwl said:2(2x+1)=22x×21
22x=(2x)2
Excuse me? You need to quit with the attitude mate.chikis said:Is everybody tired? Yet the problem is not yet finished. I brought two problem here, one has been dealt with, what about the other one? Is that the other is beyond what you can handle? Don't make me think like that please!
Mentallic said:Excuse me? You need to quit with the attitude mate.
I've also told you that you need to fix your browser or whatever the problem is so that you can read latex, because we aren't going to be bending over backwards for your every command.
It's quite amazing that you expect all the helpers in this thread to toss out their primary math display tool and be forced to work with a more crude system just for you, especially when it seems like you haven't appreciated any of the help given thus far.
chikis said:Is everybody tired? Yet the problem is not yet finished. I brought two problem here, one has been dealt with, what about the other one? Is that the other is beyond what you can handle? Don't make me think like that please!
DeIdeal said:Take a look at the Advanced Physics and Calculus & Beyond sections. Do you honestly think that there aren't people here who could solve that in a minute?
I can't believe someone has the guts to be this impolite to people who are trying to help him. You've dragged this thread on for five pages. Don't you think it's time to follow the advice people have given to you and ask your teacher about this. I'm just repeating what others have said, but you clearly need more help in maths than you can get here.
Ray Vickson said:I agree. As far as I am concerned the poster does not deserve to be helped. He wants us to do all the work, at his convenience, and to keep working away until we have finally presented him with a solution he can turn in and receive credit for (meanwhile, learning nothing). He is arrogant and stubborn, and just about the most impolite poster I have seen on this Forum.
RGV
eumyang said:[itex]2^{2x+1} - 9\cdot 2^x + 4[/itex]
Rewrite the 1st term so it looks like (something) times 22x.
azizlwl said:2(2x)2+9(2x)+4=0
(2x)2+(9/2)(2x)=-2
(2x)2+(9/2)(2x) +(9/4)2=-2+(9/4)2
If 2x confuse you, , replace it with y. Remember to replace it to original value in the final calculation.
chikis said:Sorry please,I don't mean to be this rude. Is just that the problem is still remaining one.
chikis said:Is everybody tired? Yet the problem is not yet finished. I brought two problem here, one has been dealt with, what about the other one? Is that the other is beyond what you can handle? Don't make me think like that please!
Mark44 said:Folks have been helping out on this. You would help yourself by paying attention to what these people have been saying throughout this thread.
If you don't understand what eumyang and aziz are saying above, then your next step should be to talk to your teacher, which has been suggested before in this thread.