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Simplifying equation

  1. Oct 17, 2007 #1
    I am trying to solve for the variable lambda in terms of A. After multiplying the denominator term over to the other side, how do I go on from there? I don't know how to get rid of the exponential terms.

    Thanks on advance.

  2. jcsd
  3. Oct 17, 2007 #2
    You can take the log of both sides
  4. Oct 18, 2007 #3
    Or, you can use logical reasoning to conclude that if the bases on each side are equal, then...?
  5. Oct 18, 2007 #4


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    Science Advisor

    "the bases on each side are equal" and exponential is a one-to-one function!
  6. Oct 18, 2007 #5
    After cancelling the ln's I end up with the equation below, but then it seems the lambdas cancel each other out. Is that correct? apparently from the solutions, lambda does not cancel.
  7. Oct 18, 2007 #6


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    Science Advisor

    You're equation looks correct so far, but you can reduce it to lamba in terms of A.

    Hint: Expand the binomial on the RHS.
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