- #1

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- Thread starter jahaddow
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- #1

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- #2

rl.bhat

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Simplify the attached expression using any relevant logarithmic rules

I havent really done much with logarithms, so i didnt know where to start?

Given problem can be written as

log(2)

Now use laws of logarithm to simplify.

- #3

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the problem is I dont know how to do that?

- #4

rl.bhat

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the problem is I dont know how to do that?

log(a) + log(b) = log(ab)

log(a) - log(b) = log(a/b)

- #5

HallsofIvy

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Simplify the attached expression using any relevant logarithmic rules

I havent really done much with logarithms, so i didnt know where to start?

Then you should start by learning the "relevant logarithmic rules"!the problem is I dont know how to do that?

[itex]log(ab)= log(a)+ log(b)[/itex]

[itex]log(a/b)= log(a)- lob(b)[/itex]

[itex]log(a^b)= b log(a)[/itex]

- #6

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Can somebody please demonstrate the question?

- #7

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- #8

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That advice dosent get me anywhere!

- #9

- 737

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- #10

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well that would be log(ab)

- #11

- 737

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Yes, so look at the 3 logarithm rules provided by HallsofIvy and apply them to your problem.

- #12

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ok so I'm up to log(2^2) + log(16^1/4) + log(1/4^2) - log(7/4)

- #13

- 737

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- #14

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yes ok it would be log(2^4), but then I realy am stuck on what to do next!

- #15

- 737

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well that would be log(ab)

Follow your own advice.

- #16

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I dont know how to!!!!!!

- #17

rl.bhat

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I dont know how to!!!!!!

OK.

What is 2

Substitute these values in my post #2 and simplify by using the relevant equation given by us.

- #18

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Would the answer be log(2/1.75)

- #19

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- #20

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Or would it be 12logx? I dont know.

- #21

rl.bhat

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Or would it be 12logx? I dont know.

Your answer for the first problem is correct. But write it as a single number, not in the form of a fraction.

In the second problem from where did you get log(x) along with 12?

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- #23

rl.bhat

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In that case you can write it as 8/7

- #24

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Thankyou Very Much! :D

- #25

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(18x^3 X 2x^-4)/(4x^-5 X 6x)

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