- #26

rl.bhat

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just one more question, how do I simplify this and express with positive indices.

(18x^3 X 2x^-4)/(4x^-5 X 6x)

[tex]\frac{36x^3}{x^4}\times\frac{24x}{x^5}[/tex]

Now simplify.

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- Thread starter jahaddow
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- #26

rl.bhat

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just one more question, how do I simplify this and express with positive indices.

(18x^3 X 2x^-4)/(4x^-5 X 6x)

[tex]\frac{36x^3}{x^4}\times\frac{24x}{x^5}[/tex]

Now simplify.

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- #27

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could someone plese show a bit more detail with the second problem, where did 12 come from.

- #28

rl.bhat

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could someone plese show a bit more detail with the second problem, where did 12 come from.

= [tex]\frac{4\times3\log{x}}{\log{x}}[/tex]

Now siplify.

- #29

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I missed the step before that. wheres the 3 come from?

Sorry im really bad at this.

Sorry im really bad at this.

- #30

rl.bhat

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I missed the step before that. wheres the 3 come from?

Sorry im really bad at this.

[tex]\frac{1}{\frac{1}{3}\log{x}} = \frac{3}{\log{x}}[/tex]

- #31

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2Logx^2 / 1/3Logx

= 4Logx / 1/3Logx

=4 * 3Logx / Logx

=12Logx / Logx

=12

is all the working out correct? if not can u show me the full question with working, all set out as if it were a test?

- #32

rl.bhat

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Yes. It is correct.

2Logx^2 / 1/3Logx

= 4Logx / 1/3Logx

=4 * 3Logx / Logx

=12Logx / Logx

=12

is all the working out correct? if not can u show me the full question with working, all set out as if it were a test?

- #33

- 41

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i got up to:

Log(2^4) + Log(16^1/4) + Log(1/4^2)

= Log 16 + Log 4 + Log 0.0625 - Log 1.75

Is this correct?

Then would it go:

Log(16 x 4 x 0.0625) = Log4

= Log(4/1.75)

So y have i got 4/1.75, and jahaddo has 2/1.75??

please help...

- #34

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- 0

Can someone please help!!!

why ismy answer 4/1.75 when jahaddo has 2/1.75??

HELP PLEASE!!!!

why ismy answer 4/1.75 when jahaddo has 2/1.75??

HELP PLEASE!!!!

- #35

rl.bhat

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16^1/4 = 2, not 4.

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