Simplifying Expression using Logarithms

[xX-Cyanide-Xx]

Ok i think i got it now. i got it down to 12 by doing this:

2Logx^2 / 1/3Logx
= 4Logx / 1/3Logx
=4 * 3Logx / Logx
=12Logx / Logx
=12

is all the working out correct? if not can u show me the full question with working, all set out as if it were a test?

 

[rl.bhat]

Ok i think i got it now. i got it down to 12 by doing this:

2Logx^2 / 1/3Logx
= 4Logx / 1/3Logx
=4 * 3Logx / Logx
=12Logx / Logx
=12

is all the working out correct? if not can u show me the full question with working, all set out as if it were a test?

Yes. It is correct.

 

[xX-Cyanide-Xx]

cool, but now, back to the first question.

i got up to:
Log(2^4) + Log(16^1/4) + Log(1/4^2)
= Log 16 + Log 4 + Log 0.0625 - Log 1.75
Is this correct?

Then would it go:
Log(16 x 4 x 0.0625) = Log4
= Log(4/1.75)
So y have i got 4/1.75, and jahaddo has 2/1.75??
please help...

 

[xX-Cyanide-Xx]

Can someone please help!
why ismy answer 4/1.75 when jahaddo has 2/1.75??

HELP PLEASE!

 

[rl.bhat]

16^1/4 = 2, not 4.