- #1

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How is it equal to v in the end?

I'm sorry for asking such questions. But I'm just trying to understand

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- Thread starter lioric
- Start date

- #1

- 282

- 9

How is it equal to v in the end?

I'm sorry for asking such questions. But I'm just trying to understand

- #2

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- #3

Mentor

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Can you simplify the denominator?

- #4

- 282

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Dear god I must be blindCan you simplify the denominator?

v^2-v^2 = 0

c^2 and c^2 cancels

And all that's left is a rooted v^2 which cancels itself

But look at this

This is how the same solution is illustrated in another book.

(1-u^2/c^2) cancels each other

The u^2 subtracts each other in the denominator like in the previous sollution

Which leaves a rooted u^2 / c^2

How does that simplify?

- #5

Mentor

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Look to the left of the square root sign...Which leaves a rooted u^2 / c^2

How does that simplify?

- #6

- 282

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I can see the c root What does it mean?Look to the left of the square root sign...

- #7

Mentor

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No, it's c times the root.I can see the c root What does it mean?

- #8

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So are you saying that the large root will cancel the squares of u^2 / c^2 making it like u / c * c/1No, it's c times the root.

and c and c cancels?

- #9

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Yes. Note that the author there takes only the positive root, while in the OP the two roots are kept.So are you saying that the large root will cancel the squares of u^2 / c^2 making it like u / c * c/1

and c and c cancels?

- #10

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Thank you very muchYes. Note that the author there takes only the positive root, while in the OP the two roots are kept.

- #11

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This is actually incorrect. On the right side it should be |v|, not ##\pm v##. In other words, the square root evaluates to a single nonnegative number, not two numbers.View attachment 96291

How is it equal to v in the end?

I'm sorry for asking such questions. But I'm just trying to understand

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