Simplifying Uncertainty in g: Using Derivatives to Solve for Δg

  • Thread starter Thread starter J-NCF
  • Start date Start date
AI Thread Summary
The discussion focuses on estimating the uncertainty in g using uncertainty propagation, specifically transforming equation #2 into the form of equation #1. The key formula for Δg is provided, which incorporates the uncertainties in length (l) and period (T). Participants emphasize the importance of correctly applying derivatives of g with respect to l and T, and factoring g out of the equation. A common challenge noted is the appearance of a negative sign instead of a positive one when differentiating, indicating potential algebraic errors. The conversation highlights the necessity of clearly showing work to identify mistakes and facilitate understanding.
J-NCF
Messages
1
Reaction score
0

Homework Statement


Okay so here's the background.

g=(4pi^2/T^2)l

The instructions are:
Estimate the uncertainty in g using the uncertainty propagation for a general function. The specific formula you should obtain for delta g is:

#1 Δg= g (sqrt(Δl/l)^2 + (2 ΔT/T)^2)

The uncertainty equation is :

#2 ΔF=(sqrt (partial derivative of x)^2( Δx)^2 + (partial derivative of y)^2( Δy)^2)

So basically, make equation #2 look like #1, and solve for delta g.

So the question is, how do I simplify equation #2 to look like equation #1.

F=g , x=l, and y=T is those equations.


Homework Equations


g=(4pi^2/T^2)l

#1 Δg= g (sqrt(Δl/l)^2 + (2 ΔT/T)^2)

#2 ΔF=(sqrt (partial derivative of x)^2( Δx)^2 + (partial derivative of y)^2( Δy)^2)

The Attempt at a Solution



I know the derivatives of g in relation to l and T. The professor said something about using the derivatives and replacing g into the second equation, then factoring that g out, which is how equation #1 has a g in front of the square root. I can do that with the derivative of T, however I am left with a -2 instead of a positive 2. I am missing a l for the deriative of l (obviously), so I don't really know where to go from there.
 
Last edited:
Physics news on Phys.org
Show what you have done. It may be that you have made a simple algebra mistake, but no one can tell for sure without seeing what you have done. It may also be that by writing out everything explicitly you will see your error.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top