Does f(z) have a singularity at infinity and how can its residue be obtained?

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The function f(z) = ze^(iz)/(z^2 + a^2) does have a singularity at infinity, which can be analyzed by transforming z to 1/w and taking the limit as w approaches 0. To determine the behavior of the limit, L'Hôpital's rule may be applied, and the limit can be evaluated along different paths in the complex plane, such as the imaginary axis. The discussion raises questions about how to find the residue at infinity, the implications if the limit does not exist, and the relevance of singularities at infinity in physical theories. Understanding these concepts is essential for complex analysis and its applications in integration. The conversation highlights the importance of recognizing the context of mathematical discussions.
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does f(z)=\frac{ze^{iz}}{z^2+a^2} have a singularity at infinity?

if so, how do i get the residue there?
 
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Does f(w):=f(1/z) has a singularity at w=0 is what you must ask yourself.

Btw - you're really not in the right forum.
 
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okay so i transform z -> 1/w then take lim w-> 0... if it blows up then i do have a singularity... how do i get lim w->0 of exp(i/w) ?

well first, i think i need l'hopitals (for the whole function). then, can i use the fact that when taking a limit it can be approached along any line on the Z-plane? i.e. use the path along i-axis ?

i think the conclusion will be that it blows up. three follow up questions. 1. how do i get the residue at infinity? 2. what is the conclusion in a case wherein the limit does not exist? 3. Is the singularity at infinity and/or its residue useful? (i mean i know the finite singularities are useful in integration, does this arise in some physical theory?)

i am very sorry for posting in the wrong forum.. thanks for all the help
 
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