MHB Sinx and cosx in the second quadrant

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In the second quadrant of the unit circle, sine values are positive while cosine values are negative. Therefore, if sin(x) > 0 and cos(x) < 0, it confirms that angle x is indeed located in the second quadrant. This is because points in this quadrant have positive y-coordinates and negative x-coordinates. Understanding the unit circle is crucial for visualizing these relationships. Thus, the conclusion about the angle's position is valid based on the signs of the sine and cosine functions.
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In a question we have sinx > 0 and cosx < 0.

The book says that from this we can determine that angle x is in the second quadrant. I am not understanding this leap.
 
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Think of the unit circle...in which quadrant do points on the circle have negative $x$-coordinates and positive $y$-coordinates?
 
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