Size of Force between two Point Charges

AI Thread Summary
The problem involves calculating the force between a +2.0 microC and a -0.35 microC point charge separated by 4.0 x 10^-4 m. The force is calculated using Coulomb's law, resulting in a value of -3.9 x 10^4 N. The negative sign indicates that the force is attractive, as opposite charges attract each other. Therefore, the correct interpretation is to state the force as -3.9 x 10^4 N, reflecting the direction of attraction. Understanding the signs in electrostatic force calculations is crucial for accurately describing interactions between charges.
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Homework Statement


A point charge of +2.0 microC is separated from a second point charge of -0.35 microC by a distance of 4.0 x10-4 m. Calculate the size of the force that each charge exerts on the other and its direction. (Assume 1/4 pi ε0 = 9.0 x109 m F-1)


Homework Equations



F = 1/(4 pi ε0) x (q1 x q2 / r-squared)


The Attempt at a Solution



I get an answer of -3.9 x 10 (power of 4) N

The question asks for the direction. So by stating the -'ve before the 3.9 am I indicating the direction?

Or should I state the answer is +3.9 x 10 (power of 4) N in a particular direction?

Thank you
 
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You've got the size of the force down. As for the direction: you have opposite charges, which means they attract one another. So your first answer (the negative one) is the one you should use.
 
Ok, thanks very much for the help Cryxic. It's very much appreciated. :smile:
 
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