This is my 3rd practice question that I don't know how to do :( Hoping peole can help me out, if someone could even work it out, would be greatly appriciated. A skydiver, weighing 70kg, jumps from an aeroplane at an altitude of 700 metres and falls for T1 seconds before pulling the rip cord of his parachute. A landing is said to gentle if the velocity on impact is no more than the impact velocity of an object dropped from a height of 6 metres. The distance that the skydiver falls during t seconds can be found from New- ton’s Second Law, F = ma. During the free fall portion of the the jump, we will assume that there is essentially no air resistance, so F = −mg where g = 9.8ms^−2 and m = 70kg. After the parachute opens, a significant drag term due to the air resistance of the parachute affects the force F, causing the force to become F = −mg − kv where v is the velocity and k = 110kg/sec is a drag coefficient. (a) Find the range of times T1 at which the rip cord can be pulled for a gentle landing. (b) Find the height after T1 seconds of free-fall.