Sloped Bed Truck: Acceleration & Normal Force?

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SUMMARY

The discussion focuses on the dynamics of a block on a sloped bed of an accelerating truck. When the truck accelerates horizontally, the normal force acting on the block decreases due to the acceleration. Specifically, the normal force can be expressed as mg*cos x – ma*sin x, where 'm' is the mass of the block, 'g' is the acceleration due to gravity, 'x' is the angle of the slope, and 'a' is the truck's acceleration. If the truck's acceleration exceeds a certain threshold, the normal force can become zero, indicating that the block will no longer remain on the slope.

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If I have a truck with a sloped bed in the back, the truck is accelerating horizontally and there's a block sitting on the slope tied to a rope while all this is happening. I was wondering if the trucks acceleration would cause the normal force being applied to the block by the sloped bed to diminish?

Thanks
 
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Certainly. If x is the angle between the slope and the horizontal, then initially the normal reaction was mg*cos x. If ‘a’ is the accn of the truck, then the diminished normal reaction is mg*cos x –ma*sin x. Note that the normal reaction could become zero if ‘a’ is high enough. Negative value means that the block is no more resting on the slope because the truck is accelerating so fast.

One way of calculating forces on static objects in accelerating frames is to think that there is an effective gravity of '–a' in that frame, on top of any actual gravity.
 

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