Small Oscillations around equilibrium

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Homework Help Overview

The problem involves a point pendulum subjected to a constant acceleration, requiring the derivation of equations of motion, identification of the equilibrium point, and analysis of small oscillations around that point.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the equations of motion and equilibrium point, using Taylor expansion for small oscillations. Some participants question what might be missing in the derivation process.

Discussion Status

The discussion is ongoing, with participants exploring the derivation of the equations of motion and the implications of the equilibrium point. Some guidance has been offered regarding expressing the equilibrium point in terms of the given parameters.

Contextual Notes

There are indications of confusion regarding the correct form of the frequency of small oscillations, with a correction noted in one of the posts. The participants are working within the constraints of the problem statement and the mathematical relationships derived thus far.

LiorE
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Homework Statement



The problem is: A point pendulum is being accelerated at a constant acceleration of a. Basically what's required is to find the equations of motion, the equilibrium point, and to show that the frequency of small oscillations about the e.p. is: \omega=L^{-1/2} (a^2+g^2)^{-1/4}

Homework Equations



The equation of motion I've arrived at is:

\ddot{\theta} + \frac{a\cos\theta + g\sin\theta}{L} = 0

So the e.p is:

\theta_0 = -\arctan(a/g)

The Attempt at a Solution



If we do a Taylor expansion for \eta << 1 around \theta_0:

\cos(\theta_0+\eta) = \cos\theta_0 - \eta \sin\theta_0+\ldots
\sin(\theta_0+\eta) = \sin\theta_0 + \eta \cos\theta_0+\ldots

We end up with:

\ddot{\eta} + \frac{\cos\theta_0}{L}\frac{g^2+a^2}{g} \eta = 0

Then what am I missing here?
 

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Correction:

<br /> \omega=L^{-1/2} (a^2+g^2)^{1/4}<br />
 
Anyone?
 
Seriously, can no one say anything?
 
Just saw your question.

LiorE said:
We end up with:

\ddot{\eta} + \frac{\cos\theta_0}{L}\frac{g^2+a^2}{g} \eta = 0

Then what am I missing here?

You're almost there.

Express θ0 in terms of a and g, using the arctan relation you came up with earlier. Things will simplify.
 

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