Small signal analysis of a cascode amplifier

AI Thread Summary
The discussion centers on calculating the voltage gain of a cascode amplifier through small signal analysis. The initial confusion arises from the under-determined nature of the circuit, specifically regarding the relationship at the vx node. Clarifications reveal that the voltage gain can be simplified by eliminating the M2 FET, resulting in a gain expression of Vout/Vin = -gm1*Rds1 when the load on Vout is infinite. However, with a finite load, the correct gain expression is Av = -gm1*Rds1*(1+gm2*Rds2). Understanding the role of the gate of M2 is crucial for accurate analysis.
mulothecook
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Hello there.

I am stuck trying to figure out the voltage gain of a cascode amplifier from a small signal analysis. The circuit seems to be under-determined for reasons I do not understand or maybe I am missing the perfectly obvious.

Here's my small signal model:
?temp_hash=c064e565f691e7abb408df22a4274b09.png

The only relation I can deduce without using further unknown quantities is the KCL for the vx node:
%7Bds2%7D%7D%20%3D%20v_%7Bin%7D%5Ccdot%20g_%7Bm1%7D%20+%20%5Cfrac%7Bv_x%7D%7Br_%7Bds1%7D%7D.gif

However, I need another relation to eliminate vx in order to solve for vout/vin. The small signal analysis without the cascode works just fine. May I kindly ask somebody to clarify this?M
 

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Since you have a current source supplying the M2 FET, you can eliminate M2 and the voltage gain is the same as it would be without M2, namely Vout/Vin = -gm1*Rds1.

The small signal at Vx is the same as it is at Vout as long as the load on Vout is infinite, which is the impedance of the current source feeding the drain of M2. With a finite load on Vout, this will not be the result.
 
The Electrician said:
Since you have a current source supplying the M2 FET, you can eliminate M2 and the voltage gain is the same as it would be without M2, namely Vout/Vin = -gm1*Rds1.

Could you explain why this is the case?
 
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