So, the statement is still true.

Ronnin
Messages
168
Reaction score
1
I've been playing around with some proofs and find myself relearning how I do my mathmatical thinking. Just a general question regarding how to handle something like this.

0<a<b So a and b must be positive
a/2 <b I just divided one side by two instead of "dividing through" like you would an equation. The statement is still true, would this be a legal manipulation (for whatever reason)?
 
Mathematics news on Phys.org
Ronnin said:
I've been playing around with some proofs and find myself relearning how I do my mathmatical thinking. Just a general question regarding how to handle something like this.

0<a<b So a and b must be positive
a/2 <b I just divided one side by two instead of "dividing through" like you would an equation. The statement is still true, would this be a legal manipulation (for whatever reason)?

Well, you might have to justify it, but it's still certainly true, because for positive b:

b/2 < b

And by dividing all sides of the equation by 2, you get...

0<a/2<b/2<b --> 0<a/2<b
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top