Solenoid power and conical area

AI Thread Summary
Heat generation in a tubular solenoid actuator can be calculated using the formula for resistive heating, which is I^2*R, where R is determined by the wire length and its resistance per meter. The design choice for a plunger with a flat face or conical surface area is often made to optimize force output and stroke length, with specific apex angles affecting performance. For a desired stroke of 1mm and a force output of 2500N, the current (I) can be calculated by considering factors like air permeability and the surface area of the cone. Additionally, the heating due to eddy currents in core materials can be assessed through specific formulas that account for the material properties and geometry. Understanding these calculations is crucial for effective solenoid design and performance optimization.
Skipplet
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Hello ,

I have been wanting to find out the how heat generation of a tubular solenoid (pull-type)actuator is calculated?

Secondly, why do most solenoid design use a plunger with a flat face/conical surface area . If I am looking for 1mm of stroke.. and a force output of 2500N, what apex angle of armature could I use. IF so, what would be the heat generation.

Regards
 
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Resistive heating of the windings? Eddy currents in the core material?
 
Heys,

Resistive heating due to wirings, heat generation = I^2*R.

R is found by length * (ohm/m), which is taken from American Wire Gauge
Length is found by N,no. of wire turns multiply by the average circumference of wire coil around the bobbin.

I, current is found by fixing F=2500N, air permeability, surface area of the cone, air gap is 1mm, then vary N to find I. After which able to find heat generation from resistance of wire.

Please correct me if I am wrong..!

By the way, how do I find heating due to eddy current in core materials.

Regards
 

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