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Find ▽ · F if F = x i / (x2 + y2)^3/2 + y j (x2 + y2)^3/2 .
Solution: ▽ · F = −1 / (x2 + y2)^3/2
Solution: ▽ · F = −1 / (x2 + y2)^3/2
The derivative of x/(x^2+ y^2)^{3/2}= x(x^2+ y^2)^{-3/2} with respect to x, by the product rule, is (x^2+ y^2)^{-3/2}- (3/2)(x)(2x)(x^2+ y^2)^{-5/2}scholesmu said:Find ▽ · F if F = x i / (x2 + y2)^3/2 + y j (x2 + y2)^3/2 .
Solution: ▽ · F = −1 / (x2 + y2)^3/2