Solve 2^27841 mod 34 by Hand: Discrete Math Problem Solution

raross
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could someone show me how u would solve 2^27841 mod 34 by hand? I know what theorm to use, I am just having trouble using it? Thanks
 
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What theorem would you use? Anyways, if it helps, 27841 = 11x2531 and 34 = 2x17. I found that 11 was a factor of 27841 by trial and error, and then by a lot more trial and error, found that 2531 is prime. Hopefully I didn't make a mistake in the calculations.
 
Is there any other way to do this without changing the base?
 
Euler's totient theorem?
Is a bit tricky because 34 and 2 are not co-prime.
but
2^{17} \equiv 2 \mod 34
Then we can use that
27841 \equiv 1 \mod 16
to get
2^{27841} \equiv 2^{1} \equiv 2 \mod 34
 
hrm yeah that works. How would you solve it with modular exponentiation?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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