Solve 6th Grade Enigma with Integers 8, 4, 2, 1 in Order

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The discussion centers around the challenge of creating equations using the integers 8, 4, 2, and 1 in a specific order to equal 18 and 19, while also adhering to the order of operations. Participants express skepticism about the feasibility of solving the problem if both integers and operands must remain in order. Some suggest that the exponent might be interpreted as squared, while others propose that using factorials could provide solutions, although factorials are ultimately deemed not allowed. The consensus leans towards the belief that it is impossible to meet all the specified conditions. The conversation highlights the complexity of the problem and the confusion surrounding the rules.
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This is supposed to be a 6th grade problem.

using integers 8 4 2 1 in order, create an equation to equal 18 and another to equal 19. you may use + - % X and exponents (^) in the same order.

Now if the integers and operands (including exponent) are to be in any order then the answers are simple.

8 + (4+1)*2 = 18
8*2 + 4 - 1 = 19

But, if not only the integers 8,4,2,1 are to be in order, but also the operands, then it seems impossible.

I think the integers must be in order at least. Can anyone see if it's possible or not to answer this question with integers in order but the operands in any order?

Integers are to be used once only.
Operands can be used multiple times.
 
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I don't see how the operands can even be used "in order." At most, only four will be used--and there are five given.

Anyway, my guess is that the exponent operand may have been given as ^2 (i.e., squared). Then,
(8-4)^2 + (2*1) = 18
(8-4)^2 + (2+1) = 19
 
I would guess that the order of operands is simply that the use of the operands should follow that order of preference. + - % X ^.

Nice answers. It's just that the integers are only allowed to be used once only - AFAIK!
 
Steve10 said:
you may use + - % X and exponents (^) in the same order.
If you need to use the operative in order than I must say it seems impossible.

Can you use the factorial function?
e.g.
(8 - 4! - 2) * (-1) = 18
(-8) + 4! + 2 + 1 = 19

Oh... and AFAIK?

The Bob (2004 ©)
 
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Since I can't do this problem, then thanks for saying it seems inpossible as it is.

Factorial function not included, I'm afraid :(, nice one though :)

AFAIK == As Far As I Know.
AFAIAA == As Far As I Am Aware.
 
Steve10 said:
Since I can't do this problem, then thanks for saying it seems inpossible as it is.

Factorial function not included, I'm afraid :(, nice one though :)

AFAIK == As Far As I Know.
AFAIAA == As Far As I Am Aware.

Oh ok, cool... cheers. :biggrin:

I do believe it is impossible, if the order of the numbers and the operations has to be the same as you stated. I think the best thing to do is to prove it cannot be done, rather than it can be done.

The Bob (2004 ©)
 
Maybe ...just maybe , u read the question wrongly...

Like what Knavish answered at first...maybe the operands can be used only once ...n the interger in the order...

interesting question...

ntg is impossible!
 
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