menager31
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calculus(dv/(g-kv^2))
I think it's incalculable.
Could anyone approximate it ?
I think it's incalculable.
Could anyone approximate it ?
arildno said:Since I assume you are modelling the behaviour of a mass particle in a constant gravity field including a quadratic air resistance law, I would just like to say that the proper form of resistive force R is R= -K|v|v, rather than R=-Kv^{2}
Think about it..
cks said:I have found the final answer, it's v/g. Is your calculation same with mine?
leon1127 said:because v is a vector?
i'm having a hard time following your workarildno said:You could start with a rewriting:
\int\frac{dv}{g-kv^{2}}=\frac{1}{g}\int\frac{dv}{1-(\frac{v}{\sqrt{\frac{g}{k}}})^{2}}=\frac{1}{\sqrt{gk}}\int\frac{du}{1-u^{2}},v=u\sqrt{\frac{g}{k}}
see if you can do something about that, for example along dex's line.
Alternatively, partial fractions decomposition can come to your aid.