Solve Chemistry Homework: Calculating Precipitate Mass & Solution Concentration

  • Thread starter Thread starter Physics197
  • Start date Start date
  • Tags Tags
    Chemistry
AI Thread Summary
To solve the chemistry homework problem, the balanced chemical reaction between sodium carbonate and calcium nitrate must be established. The limiting reagent concept is crucial for determining the moles of calcium carbonate and sodium nitrate produced. Calculating the mass of calcium carbonate involves multiplying the moles by its molar mass, while the concentration of sodium nitrate is found by dividing the moles by the total volume of the solution. Both reactants are used completely in a 1:1 mole ratio, simplifying the calculations. Understanding these steps is essential for accurately determining the precipitate mass and solution concentration.
Physics197
Messages
70
Reaction score
0

Homework Statement


100mL of 0.2mol/L sodium carbonate solution and 200mL of 0.1mol/L calcium nitrate solution are mixed together. Calculate the mass of the calcium carbonate that would precipitate and the concentration of the sodium nitrate solution that will be produced...


Homework Equations


Not sure.


The Attempt at a Solution


Its supposed to be a review question but I don't remember doing anything even close to this question.

Need help on what to do.
 
Physics news on Phys.org
Write the chemical reaction, balanced. Find the ratios involved and set up the resulting concentration resulting for the sodium nitrate and the mass for calcium carbonate.
 
Would you use the idea of the limiting reagent to determine how many moles you have of calcium carbonate and sodium nitrate?

Then multiply the moles of calcium carbonate by the molar mass to get the mass

and divide the number of moles of sodium nitrate by the total volume to get the concentration?
 
Physics197 said:
Would you use the idea of the limiting reagent to determine how many moles you have of calcium carbonate and sodium nitrate?

Yes; that is an excellent idea.

Then multiply the moles of calcium carbonate by the molar mass to get the mass

and divide the number of moles of sodium nitrate by the total volume to get the concentration?

Convert your starting quantities into moles of each. Your reaction stoichiometry will tell you which reactant is the limiting reactant.
 
I got 0.02 moles of each, and since it has a mole ratio of 1:1, this would mean that both would be completely used up? and wouldn't matter which one I used to calculate the other stuff
 
2xYes.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top