MHB Solve Completing Square Problem: ((x2)/18)-(x/9)=1

  • Thread starter Thread starter wellyn
  • Start date Start date
  • Tags Tags
    Square
AI Thread Summary
To solve the equation (x^2)/18 - (x/9) = 1, the first step is to eliminate the denominators by multiplying through by 18, resulting in the equation x^2 - 2x = 18. Next, to complete the square, half the coefficient of the linear term (-2) is squared and added to both sides. This results in a new equation that can be solved for x. The discussion highlights the process of completing the square as a method to simplify and solve the quadratic equation effectively.
wellyn
Messages
2
Reaction score
0
help I am stumped on this ((x2)/18)-(x/9)=1(Headbang)(Headbang)(Headbang)(Headbang)
 
Mathematics news on Phys.org
Re: competing the square

wellyn said:
help I am stumped on this ((x2)/18)-(x/9)=1(Headbang)(Headbang)(Headbang)(Headbang)

We are given:

$$\frac{x^2}{18}-\frac{x}{9}=1$$

I think I would first multiply through by the lowest common denominator to get rid of the denominators. So, multiplying through by 18, we get:

$$x^2-2x=18$$

Can you proceed?
 
Re: competing the square

no sorry I am stumped
 
Re: competing the square

wellyn said:
no sorry I am stumped

You want to take half the coefficient of the linear term (the term with $x$ as a factor) and square it, and add this to both sides. What do you get?
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Replies
7
Views
26K
Replies
5
Views
3K
Replies
1
Views
1K
Replies
2
Views
1K
Replies
3
Views
4K
Replies
19
Views
3K
Back
Top