Solve Current Draw for Resistor 0.256 W 210 Ω - Homework Help

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To determine the maximum current a 210 Ω resistor can draw with a power rating of 0.256 W, the relevant formula is P = I²R. By rearranging this equation, the maximum current (I) can be calculated using I = √(P/R). Substituting the values, I = √(0.256 W / 210 Ω) yields the maximum current. The discussion emphasizes the application of Ohm's Law and the relationship between power, current, and resistance. Understanding these concepts is crucial for solving similar problems in electrical engineering.
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Homework Statement



The power rating of a resistor is 0.256 W. If the value of the resistor is 210 Ω, what is the maximum current it can draw?

Homework Equations





The Attempt at a Solution


I feel like I am missing a variable. Help Please !
 
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jmatthews1991 said:

Homework Statement



The power rating of a resistor is 0.256 W. If the value of the resistor is 210 Ω, what is the maximum current it can draw?

Homework Equations





The Attempt at a Solution


I feel like I am missing a variable. Help Please !

No, you have everything you need.
Suppose the resistor draws a current I, what is the power it dissipates?
 
P=vi
 
still very confuesed
 
jmatthews1991 said:
P=vi

now give a formula for the power with only I and R in it (wich are known).

hint: ohm's law
 
P=(IR)I ! ! ! ! Thank you so much !
 
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