Solve Current Draw for Resistor 0.256 W 210 Ω - Homework Help

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SUMMARY

The maximum current that a resistor with a power rating of 0.256 W and a resistance of 210 Ω can draw is calculated using the formula P = I²R. By rearranging this formula, the maximum current (I) can be determined as I = √(P/R). Substituting the values, I = √(0.256 W / 210 Ω) results in a maximum current of approximately 0.0356 A. This calculation confirms that all necessary variables are present for solving the problem.

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Homework Statement



The power rating of a resistor is 0.256 W. If the value of the resistor is 210 Ω, what is the maximum current it can draw?

Homework Equations





The Attempt at a Solution


I feel like I am missing a variable. Help Please !
 
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jmatthews1991 said:

Homework Statement



The power rating of a resistor is 0.256 W. If the value of the resistor is 210 Ω, what is the maximum current it can draw?

Homework Equations





The Attempt at a Solution


I feel like I am missing a variable. Help Please !

No, you have everything you need.
Suppose the resistor draws a current I, what is the power it dissipates?
 
P=vi
 
still very confuesed
 
jmatthews1991 said:
P=vi

now give a formula for the power with only I and R in it (which are known).

hint: ohm's law
 
P=(IR)I ! ! ! ! Thank you so much !
 

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