Solve Distance: Baseball Player Sliding w/ 7.9 m/s & 0.41 Coefficient

[Huskies213]

Can anyone help me to solve for the distance here ?? I'm lost ...

A baseball player slides with an initial speed of 7.9 m/s. If the coefficient of kinetic friction between the player and the ground is 0.41, how far does thet player have to slide before comming to rest ?

 

[jamesrc]

Can you calculate the magnitude of the deceleration (Hint: make a free body diagram and use Newton's second law; the mass of the player will cancel out)?

(You can also use the work-energy theorem if you have covered that in class.)

 

[Huskies213]

Re

can anyone expand on this explanation ? I am still lost

 

[teken894]

u could calculate force that will decelerate the baseball player using the coefficient of kinetic friciton

\mu_k = \frac{F_{fr}}{F_{N}}figure out the deceleration from that force...
\frac{F}{m_{player}}=a_{player}

then use a kinematic equation to solve for distance
probably

{v_0^2} = {v_1^2} + 2ax

 

[jamesrc]

The only force acting on the player is friction, so Newton's second law gives:

F_{net} = ma = f = -\mu mg

The mass cancels out when you solve for a:

a = -\mu g

Now that you have the magnitude of the acceleration, you can use the kinematic equation suggested by teken894, which should be written:

v^2 = v_o^2 + 2a\Delta x

 

[VietDao29]

Now that you have the magnitude of the acceleration, you can use the kinematic equation suggested by teken894, which should be written:

v = v_o^2 + 2a\Delta x

Nope, it shouldn't be written like that. It should instead read:
v ^ 2 = v_0 ^ 2 + 2ad
Note that it's v² not v. :)

 

[jamesrc]

Oops. Sorry about the typo. Fixed now.