Solve Efficiency Q: Input Current for 117V Stereo Amp

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The discussion revolves around calculating the input current for a stereo amplifier with a power supply output of 22 volts at 2.8 amps and an efficiency of 78%. The output power is determined to be 61.6 watts, leading to an input power requirement of 79 watts. The correct calculation for input current from a 117-volt source shows that the input current is approximately 0.67 amps, not 1.48 amps as initially stated. The confusion arises from the misconception that input current must always exceed output current, while in reality, input voltage can affect these values. The key takeaway is that while power input must be greater than power output, current and voltage can vary independently.
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Homework Statement


The power supply for a stereo amp develops an output of 22 volts at 2.8 amps. If the overall efficiency of the power supply is 78%, what is the input current that it will draw from a 117 volt source.

Homework Equations


P = EI

The Attempt at a Solution



Eo = 22 V
Io = 2.8 Amps

Po = 22 * 2.8 = 61.6 watts

Pi = 61.6 / .78 (efficiency) = 79.0 watts
Ei = 117 V

Ii = 117 / 79.0 = 1.48 ampsBasically is this right?
I thought what you put in always has to be bigger then what you get out?
if so then how can 1.48 amps in = 2.8 amps out? :confused:
 
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JeeebeZ said:
I thought what you put in always has to be bigger then what you get out?

This principle is referring to the power. The power you put in is always greater than the power you get out. This is not true for the current or the voltage. You can have a lower input current @ a higher input voltage as in this case.

Also you have a mistake. When you wrote

JeeebeZ said:
Ii = 117 / 79.0 = 1.48 amps

you actually meant Ii = 79/117 because Ii = Pi/Ei
 
I wrote it wrong but i calculated it right... >_<
 
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