Solve for Apparent Weight: Newton's Second Law in Elevator Scenarios"

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In the discussion about apparent weight in elevator scenarios, participants analyze the forces acting on a 79.0 kg person in different elevator conditions. For an upward acceleration of 1.80 m/s², the apparent weight is calculated as 916.4 N, while at constant speed, it is 774.2 N. The conversation emphasizes the importance of drawing free-body diagrams to visualize the forces involved. Participants encourage each other to apply similar reasoning to solve for the apparent weight when the elevator accelerates downward at 1.70 m/s². Overall, the thread focuses on understanding Newton's Second Law in practical scenarios involving elevators.
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A 79.0 kg person stands on a scale in an elevator. What is the apparent weight in each of the following situations?
(a) when the elevator is accelerating upward with an acceleration of 1.80 m/s2
? N

(b) when the elevator is moving upward at a constant speed
? N

(c) when the elevator is accelerating downward with an acceleration of 1.70 m/s2
? N
 
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1. Draw a freebody diagram for each case.

2. How would you measure apparent weight. How would you write an expression involving the forces shown on a freebody diagram and the apparent weight?

3. Include your reasoning/solution before asking for help :smile:

Cheers
Vivek
 
Here Is What I Came Up With

A. FN=mg+ma
(79.0*9.8)+(79.0*1.80)=916.4

B. (79.0*9.8)+(79.0*0)=774.2

I still don't know how to get the answer for c
 
Did you draw a new FBD for part c and go through the process of summing the forces again?
 
faust9 said:
Did you draw a new FBD for part c and go through the process of summing the forces again?

You're this : . : close from solving part (c). Just go ahead and follow faust9's advice and you'll be through (if you could you parts (a) and (b) there's no reason why you can't get (c) since the reasoning is similar...only the forces are to be accounted for correctly).

Cheers
Vivek
 
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