Solve for Equivalent Resistance - Resistor is shorted?

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SUMMARY

The discussion focuses on calculating equivalent resistance (Req) in a circuit where a 75-ohm resistor is shorted. The correct calculation involves recognizing that the 75-ohm resistor is effectively a short circuit due to being in parallel with a zero-resistance wire, leading to the formula (3 || 30) || 7.5 = 2 ohms. The user initially attempted to solve the circuit without redrawing it, arriving at the same result of 2 ohms, confirming that the approach is valid when the circuit is deformed appropriately.

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zr95
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Homework Statement


I'm studying for a test and since this is technically a textbook problem I figured I'd post here to prevent being flagged.
upload_2016-9-25_14-6-36.png

I have the circuit redrawn.
upload_2016-9-25_14-3-32.png


Homework Equations


Series: Req = R1+R2...
Parallel: 1/Req= 1/R1 + 1/R2...

The Attempt at a Solution


I want to understand why when solving this circuit for Req it is (3 || 30) || 7.5 = 2ohms.
According to the solution I'm looking at the 75 ohm resistor is considered a short and no current flows across this? I don't understand why this is the case.

Also I was originally trying to be lazy and solve and just add things up without redrawing the circuit and ended up with 2ohms by doing:
((5||20)+2)||3 = 2ohms
Was this just coincidence?
 
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zr95 said:
I want to understand why when solving this circuit for Req it is (3 || 30) || 7.5 = 2ohms.
According to the solution I'm looking at the 75 ohm resistor is considered a short and no current flows across this? I don't understand why this is the case.
That is because the 75 ohm "resistor" is connected in parallel with a zero resistance piece of wire.

zr95 said:
Also I was originally trying to be lazy and solve and just add things up without redrawing the circuit and ended up with 2ohms by doing:
((5||20)+2)||3 = 2ohms
Was this just coincidence?
Nope, its not a coincidence - if you deform the circuit, your consideration is correct.
 
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You da man. That makes a lot of sense.
 

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