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vcsharp2003
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How do I go about solving the following equation for n? From inspection, it seems that this equation is not possible since 2n is always positive so positive + 2= 0 is impossible.
2n+ 2 = 0
2n+ 2 = 0
eys_physics said:If ##n## is supposed to be a real number (or integer) the equation has no solution. But, if ##n## can be complex the equation has solutions.
Rearranging the equation, you havevcsharp2003 said:Ok that makes sense. It is not mentioned that n is a real number. For complex solutions how would I start solving this?
So, I would express 2 in polar form and also -1 in polar form.eys_physics said:Rearranging the equation, you have
##2^n=-2## or
##2^{n-1}=-1##
Use then the polar form ##z=re^{i\theta}## of a complex number.
I think it might be easier to take original equation so we have 2n= -2, then take ln of both sides and express only -2 in polar form.eys_physics said:Rearranging the equation, you have
##2^n=-2## or
##2^{n-1}=-1##
Use then the polar form ##z=re^{i\theta}## of a complex number.
"Solve for n" means to find the value of the variable n in an equation or expression. It is typically used in algebraic or mathematical contexts.
To solve for n, you need to isolate the variable on one side of the equation and perform the necessary operations to get n by itself. This may involve using mathematical properties such as addition, subtraction, multiplication, or division.
Solving for n allows you to find the specific value of the variable in an equation or expression. This can help you solve problems, make predictions, or understand patterns in the data.
Sure, let's say we have the equation 2n + 5 = 17. To solve for n, we need to get n by itself on one side of the equation. First, we subtract 5 from both sides to get 2n = 12. Then, we divide both sides by 2 to get n = 6. Therefore, the value of n in this equation is 6.
In most cases, yes. However, there may be some equations or expressions that do not have a solution for n or have an infinite number of solutions. Additionally, some equations may have complex or imaginary solutions for n. It is important to check your work and make sure your solution makes sense in the context of the problem.