Solve for (x) in F times G: (x - 3)^2 + 2 or x^2 - 6x + 11

[sfeld]

F(X) = x^2 + 2; G(X) = x - 3

F times G

Now, I don't know if this problem is different but for the times sign for F times G, its an open circle, its not solid.

Answer is (x - 3)^2 + 2 or x^2 - 6x + 11

 

[Ethereal]

Given f(x) = x^2 + 2 and g(x) = x-3 Find fg(x) which is not quite the same as f(x)*g(x). You're supposed to find the composite function fg(x). I don't see the problem.

 

[HallsofIvy]

FoG(x) is defined as F(G(x)).

Since F(X) = x^2 + 2 and G(X) = x - 3,
F(G(x))= F(x-3)= (x-3)^2+ 2.