Solve H= (NI)/ (2(Pi)r): Calculate Current, Voltage

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The discussion focuses on solving the equation H = (NI)/(2πr) to calculate current and voltage. A participant suggests that the total resistance is 100 ohms, leading to a calculated current of 0.12 A and a voltage of 0.12 V across a 1-ohm resistor. However, there is confusion regarding the interpretation of 'H' and the treatment of the inductor in the circuit. It is emphasized that the inductor cannot be treated as a short circuit when the circuit is opened, and a KVL loop equation should be established to account for the potential drop across the inductor. The solution involves forming a differential equation and using initial values to determine constants.
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Homework Statement


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physics.jpg



Homework Equations



H= (NI)/ (2(Pi)r)
V=IR

The Attempt at a Solution



a)

total resitance = 100ohms?
from this would the current be 0.12A

over 1ohm resistor: 0.12V

not sure if this is correct even. Any help would be much appreciated.
 

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I think you misread 'H' here. H in the question doesn't refer to the magnetic field strength and the formula you provided here refers to the H-field in a torus.

Also in your answer you disregarded the inductor. Bear in mind that once you open the circuit, you can't treat the inductor as a short-circuited wire. What you should do is to write out the KVL loop equation, bearing in mind the potential drop across the inductor is L(di/dt), where i is the time-varying current through the inductor. Then you'll get a differential equation which you then have to solve for the current. Plugging in a initial value will help you find the unknown constant of integration.
 

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