Solve Idempotent Matrix Inequality: n≥p-1 | Artin's Algebra

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Homework Statement



This is from Chapter 11 of Artin's Algebra:

Let p be a prime, and let A (not the identity) be an nxn integer matrix such that A^{p}=I. Prove that n \geq p-1.

Homework Equations



This is in the factorization chapter, and the section is called Explicit Factorization of Polynomials.

The Attempt at a Solution



I don't even know where to begin. I'm guessing I need to somehow get a polynomial equation, but like I said, I don't really know where to start. Any help would be greatly appreciated!
 
Last edited:
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haven't got there yet, but hopefully these help you get started

clearly A is invertible as A^(p-1) = A^-1

also note that
A^(p+1) - A = A(A^p - I ) = 0
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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