Solve KE, PE and Work for Block Sliding Down Friction-Less Incline

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A 2kg block slides down a frictionless incline at a 20-degree angle, reaching a speed of 9 m/s. To find the vertical distance traveled, the conservation of energy principle is applied, leading to the calculation of height as approximately 4.14 m. The work done by gravity is calculated using the force of gravity (19.6 N) and the vertical displacement. The correct formula for work involves the component of displacement in the direction of the force, which is debated between using cosine or sine of the angle. The final calculations for work done by gravity are clarified, emphasizing the importance of using the correct mass and angle in the equations.
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Homework Statement


How do you solve this??

A 2kg block starts from rest slides down a friction-less incline plane that is at angle of 20degree with the horizontal. At a certain point on the incline, the speed of the block is 9m/s.

1.What is the vertical distance the block has traveled??
2.What is the work done by gravity as the block moves the vertical distance you found??





Homework Equations



Work= Force x Displacement
KE= .5mv^2
PE= mgh

The Attempt at a Solution



for number 1, I know that my PEf nd KEi =0.
So i set PEi and KEf equal to each other.
PEi=KEf.
So what i did was mgh=.5*m*v^2.
m's cancel out.

so 9.8h=.5v^2.
.. This is where i am stuck.. I am not sure if i am doing right.. But how do i find v which is velocity?
 
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I think it gives the velocity in the problem statement. (actually the speed)
 
Then how do i solve it?
 
zzoo4 said:
...

for number 1, I know that my PEf nd KEi =0.
So i set PEi and KEf equal to each other.
PEi=KEf.
So what i did was mgh=.5*m*v^2.
m's cancel out.

so 9.8h=.5v^2.
.. This is where i am stuck.. I am not sure if i am doing right.. But how do i find v which is velocity?
Solve your last equation for h.
 
I cant..
 
O~ do i just substitute 9??
 
You should be able to solve it. What is v ?
 
the speed is 9.. Okay i got #1 which is 4.14 m..

But cannot find the work done by gravity??
 
What's the force of gravity, on the block?
 
  • #10
39.24
 
  • #11
Is this right??

W= 39.24 * 4.13cos(30).

= 140??
 
  • #12
in joules??
 
  • #13
Or is it Pe=mgh??

4kg*9.8*4.13= 161J?
 
  • #14
Why 4 kg ?

(2kg )(9.8 N/kg) = ?

The weight!
 
  • #15
Oh sorry. I thought the mass was 4kg.
so its actually.

2kg * 9.8 n/kg = 19.6 N.

So what now??
 
  • #16
Work= Force x Displacement (sort of)

Actually: Work= Force x (the component of Displacement that's in the direction of the force)

the component of Displacement that's in the direction of the force = h
 
  • #17
so its.

W=19.6 N * 4.13cos(20)?
 
  • #18
or is it sin(20)??
 
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