Solve Lens Problem: Focal Length & Magnification

  • Thread starter Thread starter mustang
  • Start date Start date
  • Tags Tags
    Lens
AI Thread Summary
The discussion focuses on solving lens problems involving focal length and magnification. For problem 24, the calculations confirm that the magnification is approximately 4.02, indicating the virtual image is 4.02 times larger than the object. In problem 30, the correct distance to hold the lens from the nickel for a magnification of +2.06 is approximately 8.7 cm. Both calculations for the problems are verified as correct. The thread emphasizes understanding lens formulas and their applications in optics.
mustang
Messages
169
Reaction score
0
Lens Problems
problem 24. A person looks at a gem using a concverging lense with a focal length of 13.7 cm. The lense forms a virtual image 35.5 cm from the lense.
a) Find the magnifaction.
This is what I have done so far:
f=13.7 , q= -35.5
1/p+1/q=1/f
1/f-1/q=1/p
1/13.7-(-1/35.5)=9.88516=p
M=-q/p
=--35.5/9.88516
= 4.02333

Is this right??

Problem 30. A magnifying glass has a converging lens of focal length 17.4 cm. At what distance from a nickel should you hold this lens to get an image with a magnificaiton of +2.06? Abswer in cm.
got p=8.7 and M=1.841932169 is this right?
 
Physics news on Phys.org
You posted this same problem in College Help.
 


Yes, your calculations for both problems 24 and 30 are correct. For problem 24, the magnification is approximately 4.02, meaning the virtual image is 4.02 times larger than the object being viewed. For problem 30, the distance from the lens to the object (nickel) is approximately 8.7 cm. This means that the object should be held 8.7 cm away from the lens to achieve a magnification of +2.06. Great job!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top