Solve Limit Problem: Find a+b for ax+b=25

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Homework Help Overview

The problem involves evaluating the limit of a function as x approaches zero, specifically the expression ##\lim_{x->0}\frac{\sqrt{ax+b}-5}{x}##, and determining the values of a and b such that this limit equals ##\frac{1}{2}##. The context is rooted in calculus, particularly in the application of limits and potentially L'Hôpital's rule.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using L'Hôpital's rule and the implications of the limit approaching zero. There is an exploration of rewriting the square root expression and expanding it using power series. Questions arise regarding the conditions necessary for applying L'Hôpital's rule and what must be true for the limit to be valid.

Discussion Status

The discussion includes various approaches to the problem, with some participants suggesting specific values for b and a based on their reasoning. There is an indication that productive lines of inquiry are being explored, particularly around the implications of the limit and the relationships between a and b.

Contextual Notes

Participants are working under the constraints of the limit approaching zero and the requirement for the limit expression to yield a specific value. The original poster expresses difficulty in progressing after an initial application of L'Hôpital's rule, indicating potential gaps in understanding the necessary conditions for the limit.

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Homework Statement



If a and b satisfy ##\lim_{x->0}\frac{\sqrt{ax+b}-5}{x} = \frac{1}{2}##, then a+b equals...

A. -15
B. -5
C. 5
D. 15
E. 30

Homework Equations


L'hospital

The Attempt at a Solution



By using L'hospital, I get b=a^2

Then, I got stuck.. Substituting b=a^2 into the limit equation, but I still can't cancel out the x which is the cause of zero denominator..
Please help
 
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Since ##x \to 0##, you can write ##\sqrt{ax+b} = \sqrt{b} \sqrt{1+\frac{ax}{b}}## and then expand ##\sqrt{1+\frac{ax}{b}}## into power series. You will be able to determine ##b## first thanks to the presence of ##-5## in the numerator.
 
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terryds said:

Homework Statement



If a and b satisfy ##\lim_{x->0}\frac{\sqrt{ax+b}-5}{x} = \frac{1}{2}##, then a+b equals...

A. -15
B. -5
C. 5
D. 15
E. 30

Homework Equations


L'hospital

The Attempt at a Solution



By using L'hospital, I get b=a^2

Then, I got stuck.. Substituting b=a^2 into the limit equation, but I still can't cancel out the x which is the cause of zero denominator..
Please help
What must be true for ##\displaystyle \ \frac{\sqrt{ax+b}-5}{x}\ ## if L'Hôpital's rule can be applied? In particular what must be true of ##\displaystyle \ \lim_{x->0}(\sqrt{ax+b}-5) \ ?##
 
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SammyS said:
What must be true for ##\displaystyle \ \frac{\sqrt{ax+b}-5}{x}\ ## if L'Hôpital's rule can be applied? In particular what must be true of ##\displaystyle \ \lim_{x->0}(\sqrt{ax+b}-5) \ ?##

It must be zero!
So, b equals 25

and a equals 5

a+b = 30..

Thanks a lot!
 

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