Solve: log6 36 = 5x+3

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I got an answer, but I cannot get it to check correctly:

=6 ^5x+3 =36
=6 ^5x+3 = 6^2
=5x+3 =2
=5x = -3+2
=5x = -1
x= 1/5

But I put 1/5 into the equation and it does not work out correctly.
 

dav2008

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Check your work again. I think you'll laugh.
 

arildno

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Rusho said:
I got an answer, but I cannot get it to check correctly:
this equality sign means??->=6 ^(5x+3) =36 Missing parentheses:mad:
(=)6 ^(5x+3) = 6^2
Totally incorrect use of equality sign! :mad:-> =5x+3 =2
Totally incorrect use of equality sign! :mad:->=5x = -3+2
(=)5x = -1
x= 1/5
Where did the minus sign go???
 
24
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Without the equals

6 ^5x+3 =36
6 ^5x+3 = 6^2
5x+3 =2
5x = -3+2
5x = -1
5x/5 = -1/5
x= - 1/5

OH I see now I get "2" and 6^2 =36 :)
 

arildno

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[tex]6^{5*(-\frac{1}{5})+3}=6^{-1+3}=6^{2}=36[/tex]
your problem being?
 

AKG

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Your problem was on the last lines:

5x = -1
x= 1/5


You forgot about the minus sign.
 

Curious3141

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You should try being more negative. :rofl: :rofl:
 

arildno

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Curious3141 said:
You should try being more negative. :rofl: :rofl:
:mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :biggrin:
 

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