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Solve: log6 36 = 5x+3

  1. May 20, 2006 #1
    I got an answer, but I cannot get it to check correctly:

    =6 ^5x+3 =36
    =6 ^5x+3 = 6^2
    =5x+3 =2
    =5x = -3+2
    =5x = -1
    x= 1/5

    But I put 1/5 into the equation and it does not work out correctly.
     
  2. jcsd
  3. May 20, 2006 #2

    dav2008

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    Check your work again. I think you'll laugh.
     
  4. May 20, 2006 #3

    arildno

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    this equality sign means??->=6 ^(5x+3) =36 Missing parentheses:mad:
    (=)6 ^(5x+3) = 6^2
    Totally incorrect use of equality sign! :mad:-> =5x+3 =2
    Totally incorrect use of equality sign! :mad:->=5x = -3+2
    (=)5x = -1
    x= 1/5
    Where did the minus sign go???
     
  5. May 20, 2006 #4
    Without the equals

    6 ^5x+3 =36
    6 ^5x+3 = 6^2
    5x+3 =2
    5x = -3+2
    5x = -1
    5x/5 = -1/5
    x= - 1/5

    OH I see now I get "2" and 6^2 =36 :)
     
  6. May 20, 2006 #5

    arildno

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    [tex]6^{5*(-\frac{1}{5})+3}=6^{-1+3}=6^{2}=36[/tex]
    your problem being?
     
  7. May 20, 2006 #6

    AKG

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    Your problem was on the last lines:

    5x = -1
    x= 1/5


    You forgot about the minus sign.
     
  8. May 20, 2006 #7

    Curious3141

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    You should try being more negative. :rofl: :rofl:
     
  9. May 21, 2006 #8

    arildno

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    :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :biggrin:
     
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