Solve Mass to Volume Problem: Ca + 2H2O -> Ca(OH)2 + H2

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The discussion revolves around a mass to volume problem involving the reaction of calcium with water to produce hydrogen gas. The initial equation presented was incorrectly balanced, leading to confusion about the stoichiometry of hydrogen production. After balancing the equation correctly as Ca + 2 H2O -> Ca(OH)2 + 2 H2, the calculation for moles of calcium and the resulting volume of hydrogen gas was discussed. The calculated volume of hydrogen gas at STP was 11.2L, but participants argued that the correct volume should be 5.59L due to the misinterpretation of the stoichiometric coefficients. The consensus is that the initial equation's misbalance significantly affected the final answer.
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[SOLVED] Mass to Volume Problem

I have a mass to volume sample problem in my textbox and the answer seems to be wrong. Could someone please look this over and let me know if the answer to the sample problem is in fact wrong?
Thanks very much!

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What volume of H2(g) at STP can be produced when 10.0g of calcium is reacted with excess water?

Ca(s) + 2 H2O(l) -> Ca(OH)2(s) + H2(g)

1. Balance the equation: Ca + 2 H2O -> Ca(OH)2 + 2 H2
(Where does the 2 in 2 H2 come from? This is an unbalanced equation.)
2. Find the moles of Ca reacted: mol Ca = 0.2494mol
3. Proportionality: x/2 = 0.2494mol/1 for which x = 0.4988mol
(Again the 2 from 2 H2 is used here, which is why I think the answer is wrong.)
4. Volume of H2: 0.4988mol x 22.4L/mol = 11.2L
(Shouldn’t the answer be 5.59L?)
 
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I agree with you, there should not be a 2 infront of H2 in the equation and the answer should be 5.59L
 
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