Solve Momentum Problem: Ice Skater & Cube

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The problem involves a 90 kg styrofoam cube and a 60 kg ice skater on a frictionless surface. When the skater pushes off the cube, conservation of momentum must be applied to determine their movements. The key is to establish a relationship between their velocities and distances traveled, as they will be inversely proportional due to their differing masses. By substituting velocity with distance over time, the time variable can be eliminated, simplifying the equations. Understanding these relationships is crucial to solving the problem effectively.
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Homework Statement


A large, uniform-density cube of styrofoam has a side length of 3.0 m and a mass of 90 kg. It is at
rest on a horizontal, frictionless (ice) surface. An ice-skater with a mass of 60 kg is standing at rest,
touching one face of the cube. You should consider all of the ice-skater's mass to be located exactly at
the position of the cube's side. The ice-skater now pushes off against the cube. When the cube has
moved 4.0 m from its starting position, how far has the ice-skater moved?

Homework Equations


mvi=mvf,
hard to tell what other equations come into play[/B]

The Attempt at a Solution


tried to use conservation of momentum equation (mvi=mvf) to solve, but ended up falling short since I can't determine the velocities of the cube and the ice-skater. I know information about the side length of the cube and the ice skater's position on the cube will be important in figuring out the problem, but i just can't see how they are connected.
 
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The conservation of momentum equation will give you one equation with two unknowns - you need to find another equation (or two) in those unknowns.

You have yet to use the distances - what is the relationship between the distance traveled and the velocity?

Note: you can also do this in terms of ratios - what is the skaters speed as a fraction of the cube's?
What does that suggest about the distances they travel in the same time?
 
I tried to use conservation of momentum equation (mvi=mvf) to solve, but ended up falling short since I can't determine the velocities of the cube and the ice-skater.

What Simon said.

Write your equations.
Substitute Velocity = distance/time

You might find that the time cancels :-)
 
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