Solve Parseval's Identity for 1+\frac{1}{9}+\frac{1}{25}+\cdot\cdot\cdot

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Homework Statement


Obtain the result of the infinite sum 1+\frac{1}{9}+\frac{1}{25}+\cdot\cdot\cdot

By applying Parseval's Identity to the Fourier series expansion of
0 if -\frac{\pi}{2} < x < \frac{\pi}{2}
1 if \frac{\pi}{2} < x < \frac{3\pi}{2}

Homework Equations



2a_0^2+\sum_n{(a_n^2+b_n^2)}\leq\frac{1}{\pi}\int_{-\pi}^{\pi}\! f^2(x) \, \mathrm{d}x.

The Attempt at a Solution



I got the solution to the Fourier series, and I know it's correct.

The terms for a_n in the Fourier series expansion are \frac{-2}{n\pi} if n=1,5,9,13,..., and \frac{2}{n\pi} if n=3,7,11,15,...
The b_n terms are 0, since it is an even function about 0.

I'm just not sure how to use this information in Parseval's Identity.
 
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so write your sum out and see if you can relate it to the given series

in the infinite limit the inequality becomes equality, and the integral should be easy to evaluate
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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