Solve Radiation Problem: Find Temp as Function of Time

AI Thread Summary
To solve the radiation problem for the satellite sensor, the equilibrium temperature can be calculated using the formula T=((a_sw/a_LW)*(Fs/omega))^1/4, where Fs is the solar flux and omega is the Stefan-Boltzmann constant. The temperature as a function of time can be expressed with the equation m*c*(dT/dt)=A*omega*T^4, considering the area and mass of the sensor. If the sensor's mass is negligible, it suggests that the satellite maintains a constant equilibrium temperature. Additionally, the differing areas for sunlight absorption and infrared emission must be considered based on the satellite's orientation. Understanding these factors is crucial for accurately determining the temperature dynamics of the sensor.
Physics-101
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Homework Statement


We have a sensor onboard a satellite that is faced towards Earth, from the Sun. The LW absorptivity is 0.8 (a_LW) and SW is 0.2 (a_SW).
I need to find a equation for the temperature as a function of time. Given datas is the Area=0.3 m^2 and Specific Heat of 4 J/K

Homework Equations


See below.

The Attempt at a Solution


I think that I need to calculate the equilibrium temperature, which I did by using T=((a_sw/a_LW)*(Fs/omega))^1/4,
Fs=solar flux=1368 W/m^2 and omega= Stefan-Boltsmann constant.

Later, one equation that I have in mind for the temperature as a function of time is:
m*c*(dT/dt)=A*omega*T^4 , where A= area and m= mass. The sensor might be really small, so the mass m is negligible (?). What should I do now, I'm stuck.

Thanks!
 
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Have you thought of anything else to help solve the problem?
 
Physics-101 said:
Later, one equation that I have in mind for the temperature as a function of time is:
m*c*(dT/dt)=A*omega*T^4 , where A= area and m= mass. The sensor might be really small, so the mass m is negligible (?).
A negligible mass is equivalent to a satellite that is always at its equilibrium temperature .

You'll have different areas for absorption of sunlight and emission of infrared light, and those areas depend on the orientation of the satellte.
 
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