Solve Secx=-5.2 | Find Solutions for x Between 0 and 2π

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The discussion revolves around solving the equation sec(x) = -5.2 for x in the range [0, 2π]. One participant found two solutions: x = 1.76 and x = 4.52, but noted that the answer key only lists 1.76. Others confirmed that both solutions are valid, explaining that the second solution can be derived using the periodic nature of the cosine function. The conversation highlights the importance of understanding the properties of trigonometric functions in finding multiple solutions. Ultimately, the participants agree on the correctness of both solutions.
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Q. Solve: secx=-5.2
x is greater than or equal to zero and less than or equal to 2π

I got 1.76 and 4.52, but answer key only has 1.76.

Am I not right?
 
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I find the same answers as you do when I do a quick check using my TI-89. Hmmm :confused:
 
dragon513 said:
Q. Solve: secx=-5.2
x is greater than or equal to zero and less than or equal to 2π
I got 1.76 and 4.52, but answer key only has 1.76.
Am I not right?
Yup, that looks good to me. :smile: Your answer is correct!
 
Thank you!
 
dragon513 said:
Thank you!
Once you had the first solution 1.76, how did you find the 2nd one?
 
Since you have cos(-x) = cos(x), and \cos x = \cos (x + 2k \pi) \ \ , k \in \mathbb{Z}
So the second one is just:
- 1.76 + 2 \pi = 4.52
 
Thanks for answering, but I was asking dragon513.
dragon513, what was your approach for finding the 2nd angle?
 
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