- #1

slh3410

- 11

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## Homework Statement

Where Vs = 120 ∠0° V

## Homework Equations

All values are represented in ohms, so they are treated as resistors.

## The Attempt at a Solution

Series inductor + resistor

30+j10 ohms = 31.62∠18.435°

Parallel resistor and inductor+resistor

(1/50)= 0.02∠0°, 1/(31.62∠18.435°)= 0.0316∠-18.435°

0.02∠0° + 0.0316∠-18.435° = .050968∠-11.31°

1/(050968∠-11.31°) = 19.62∠11.31°

Series [j10+parallel section]

j10 + 19.62∠11.31° = 23.704∠35.746°

Now the current

120∠0° / 23.704∠35.746° = 5.062∠-35.746°Not sure how to set up the Voltage Division equation. I think I'm doing all the impedance calculations correctly though.

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