I am looking for the solution of [tex] C_{3.p}(t) [/tex](adsbygoogle = window.adsbygoogle || []).push({});

Edit: sorry I forgot to add the explantions for the symbols as HallsofIvy pointed rightfully out.

- There are n+m+p equations with n+m+p variables of C

- A, B, C, D, E, n, m, p are constants

using the following set of equations:

Part I

[tex]

\frac {dC_{1.1}} {dt} \frac {V_1} {n} = A . {C_{2.m}} - B . C_{1.1}

[/tex]

[tex]

\frac {dC_{1.2}} {dt} \frac {V_1} {n} = B . C_{1.1} - B . C_{1.2}

[/tex]

[tex]

\frac {dC_{1.3}} {dt} \frac {V_1} {n} = B . C_{1.2} - B . C_{1.3}

[/tex]

... up to n equations for C1

[tex]

\frac {dC_{1.n}} {dt} \frac {V_1} {n} = B . C_{1.(n-1)} - B . C_{1.n}

[/tex]

Part II

[tex]

\frac {dC_{2.1}} {dt} \frac {V_2} {n} = B . C_{1.n} + C . C_{3.m} - D . C_{2.1}

[/tex]

[tex]

\frac {dC_{2.2}} {dt} \frac {V_2} {n} = D . C_{2.1} - D . C_{2.2}

[/tex]

[tex]

\frac {dC_{2.3}} {dt} \frac {V_2} {n} = D . C_{3.2} - D . C_{2.3}

[/tex]

... up to m equations for C2

[tex]

\frac {dC_{2.m}} {dt} \frac {V_2} {n} = D . C_{2.(m-1)} - D . C_{2.m}

[/tex]

Part III

[tex]

\frac {dC_{3.1}} {dt} \frac {V_3} {n} = E . C_{2.m} - E . C_{3.1}

[/tex]

[tex]

\frac {dC_{3.2}} {dt} \frac {V_3} {n} = E . C_{3.1} - E . C_{3.2}

[/tex]

[tex]

\frac {dC_{3.3}} {dt} \frac {V_3} {n} = E . C_{3.2} - E . C_{3.3}

[/tex]

... up to n equations for C3

[tex]

\frac {dC_{3.p}} {dt} \frac {V_3} {n} = E . C_{3.p-1} - E . C_{3.p}

[/tex]

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# Solve set of differential equations

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