Solve Shear Stress with Expert Tips

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Discussion Overview

The discussion revolves around solving a problem related to shear stress in bolts, focusing on the application of formulas and concepts related to shear forces and cross-sectional areas. Participants seek assistance in understanding the calculations involved.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant requests help with a specific problem related to shear stress and expresses appreciation for any assistance.
  • Another participant inquires about the formula needed to solve the problem and asks how many cross-sections must be sheared for any to be sheared, requesting a demonstration of the work involved.
  • A third participant discusses the concept of planes of shears, explaining that each bolt experiences two planes of shear in a double shear state, and provides a method to calculate average shear stress using the total load and cross-sectional area.
  • A fourth participant identifies themselves as a metal professional and offers assistance to the original poster.

Areas of Agreement / Disagreement

The discussion includes multiple viewpoints, with participants providing different aspects of the problem without a clear consensus on the approach or solution.

Contextual Notes

Participants have not fully established the necessary assumptions or definitions for the problem, and there are unresolved mathematical steps in the discussion.

Who May Find This Useful

Individuals interested in mechanical engineering, materials science, or those studying shear stress and its applications in structural analysis may find this discussion relevant.

samtrix
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attached is my problem.

any help will be appreciated!

thanks!
 

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Do you have a formula?
How many cross-sections must be sheared in order for any to be sheared?
Please start and show your work.
 
What do you know about planes of shears?

In your example each bolt will have 2 planes of shears, making the bolt in a double shear state. Which means each of the shear forces will be equal to the half of the total load transmitted per bolt.

With this in mind you know the total load is simply 80 kiloNewtons, and for a bolt the average shear stress will be equal to the shear force divided by the cross section of the area where it acts. You have the total load, you have the allowed shear stress, and the only unknown is the diameter, so simply by using the equation you have stated, you can solve for the diameter of the bolts.

Remember: you have 2 cross section areas, because you have two bolts (which should be accounted in A).
 
I am a metal http://www.scissorsforsale.com/ professional, I would like to help you if you need.
 
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