Solve sin(x-y) for x and y in [0,pi/2] and [pi/2,pi]"

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The discussion revolves around the confusion regarding the notation used in the problem "Solve sin(x-y) for x in [0, pi/2] and y in [pi/2, pi]." Participants express uncertainty about whether this means to evaluate sin(x-y) at specific points or to solve for x and y. There is a consensus that the phrasing is non-standard and potentially meaningless, with suggestions that it might actually involve solving an equation like sin(x-y) = 0 or finding extrema. One participant proposes rewriting the function using trigonometric identities for clarity. The overall sentiment is that the problem's wording lacks precision and clarity.
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Solve sin(x-y) when x= [0, pi/2], y=[pi/2, pi].

I am just not familier with the notations.

Does the above mean that I need to find the value of sin (x-y), for (x,y)= (0, pi/2) and (pi/2, pi)?

Why would they write x and y like this??
Thanks.

Gamma
 
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I haven't the slightest idea of what they have meant. The notation, if not meaningless, is at the very least obscure and non-standard.
 
What, exactly, is the wording of the problem? You can solve an equation or, more generally, a "problem" but you can't "solve" a function.
"Solve sin(x-y)" makes no sense. Does the problem ask you, possibly to solve "sin(x-y)= 0" or to find maximum and minimum values for the function?
 
Thanks guys for the replies.

This is exactly the wording of the problem.

I do felt the same way as you felt. Meaningless question. Only way I would do this is to write sin(x-y)= sinx cosy - cosx siny and substitue values.

Thanks,

Gamma.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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