Solve Stokes Equation Help: Homework Statement

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The discussion focuses on solving a problem involving Stokes' Theorem with a specific vector field and curve defined by a cylinder and a plane. The user initially attempts to apply Stokes' Theorem, calculating the normal to the plane and setting up the integral. They explore parameterizing the curve but encounter difficulties with their chosen parameters. The conversation highlights the equivalence of using Green's Theorem and Stokes' Theorem, noting that both approaches ultimately lead to the same challenges with the integral involving sin(xyz). The thread emphasizes the complexity of the problem and the need for careful consideration of the parameterization and integration methods.
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Homework Statement


let F be vector field:
\[\vec F = \cos (xyz)\hat j + (\cos (xyz) - 2x)\hat k\]
let L be the the curve that intersects between the cylinder \[(x - 1)^2 + (y - 2)^2 = 4<br /> \] and the plane y+z=3/2
calculate:
\[\left| {\int {\vec Fd\vec r} } \right|\]

Homework Equations


in order to solve this i thought of using the stokes theorem because the normal to the plane is \[\frac{1}{{\sqrt 2 }}(0,1,1)\]
thus giving me
\oint{Fdr}=\int\int{curl(F)*n*ds}=\int\int{2/sqrt{2}*\sin(xyz)}


i tried to parametries x y and z x= rcos(t)+1 y=rsin(t)+2 z=1/2-rsin(t)

but it won't work
 
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Would x = 1 + 2 cos(t), y = 2 + 2 sin(t) and z = -1/2 - 2 sin(t) do the trick?
 


i wonder if it is allowed given we have to do a multiple integral needing 2 variables
 


Why wouldn't you just use Green's?
 


using green or stokes is the same thing green is just a private solution of stokes and if you use it you are still stuck with that sin(xyz)
 


See what Halls answered you in the other thread.
 
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