Solve Tangential Speed Equation: Planet Radius 5.99x10^6 m, G-Accel 7.87 m/s^2

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To find the tangential speed at the equator of a planet with a radius of 5.99x10^6 m and a gravitational acceleration of 7.87 m/s^2, one must equate centripetal acceleration to gravitational acceleration. The relevant formula for tangential velocity is Vt = rW, where W represents angular velocity. The problem highlights confusion regarding the setup, indicating that the student has struggled with this specific question amidst a larger homework set. Assistance is sought to clarify the relationship between centripetal and gravitational acceleration. Solving this will yield the required tangential speed for a person at the equator.
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Homework Statement



If the rotation of a planet of radius 5.99x10^6 m and free-fall acceleration 7.87 m/s^2 increased to the point that the centripetal acceleration was equal to the gravitational acceleration at the equator, what would be the tangential speed of a person standing at the equator?


Homework Equations


Vt=rW (tangential velocity equals radius times omega, or angular velocity)


The Attempt at a Solution


I don't even know how to go about solving this. The way the problem is set up is confusing to me. This is the only problem out 30 some-odd questions that I have not done correctly. My homework is due at 12:00 tonight and I have almost an A, but this question is really bothering me. Can someone help?
 
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I hope you're not on Eastern Standard Time. You are given the gravitational acceleration. What's the formula for centripetal acceleration? Set them equal.. you'll be going real fast...
 

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