Solve the Physics 101 Problem: Golf Cart and Walking Speeds

  • Thread starter Thread starter spoonthrower
  • Start date Start date
  • Tags Tags
    Cart Golf Physics
AI Thread Summary
The discussion revolves around a physics problem involving a golfer's trip in a golf cart and her subsequent walking. The golfer travels in the cart at 3.10 m/s for 21.0 seconds, and then walks at 1.20 m/s. The goal is to determine how long she must walk to achieve an average speed of 1.90 m/s for the entire trip. Participants express confusion over calculating average speed when distances and times for both segments are not fully provided. The conversation highlights the importance of understanding the relationship between distance, speed, and time in solving the problem.
spoonthrower
Messages
36
Reaction score
0
A golfer rides in a golf cart at a speed of 3.10 m/s for 21.0 s. She then gets out of the cart and starts walking at an average speed of 1.20 m/s. for how long (in sec) must she walk if her average speed for the entire trip, riding and walking, is 1.90 m/s?

I know average speed = d/t I'm just confused b/c the distance and the time for the walking part is not given. Please help. Thanks.

This HW problem is for my college physics 101 class and nobody has any ideas? c'mon
 
Last edited:
Physics news on Phys.org
You are given all but how long she walks, and that is what you are supposed to find. How do you calculate the average speed where there are two parts to it? Hint -- speed is distance / time as you indicate. What is the total distance she traveled while on the cart? What would be the total distance she walked, if you knew the time?
 
Have you forgotten that you ... posted this .. already ? Or you just don't like bumping threads ?
 
Rozenwyn said:
Have you forgotten that you ... posted this .. already ? Or you just don't like bumping threads ?
Wow, and you even wrote out the equation for them in that thread. Weird, why re-post?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Finding time from average speed
Replies
7
Views
2K
Solve the Golf Cart Physics Problem & Find Total Trip Time | Physics 101 HW Help
Replies
1
Views
3K
Homework problem: Average speed and time
Replies
1
Views
3K
Kinematics - velocity of golfer
Replies
1
Views
6K
Average speed of person walking
Replies
1
Views
4K
Average speed of person walking problem
Replies
2
Views
5K
How much work, speed and distance
Replies
15
Views
5K
Average Speed Between Points A & B: 0 m/s
Replies
4
Views
1K
Calculating Average Speed: Physics Homework Problem
Replies
13
Views
2K
Physics 2101 Problem: Golf Ball Momentum & Force
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top