Solve the Strange House Puzzle - One Doorway Left!

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The discussion revolves around a puzzle involving a house with five rooms, each having doorways on every wall, and the challenge is to find a continuous path that passes through each doorway exactly once. Participants express frustration in trying to solve the problem, noting that any attempted path inevitably leaves one doorway unvisited. The conversation draws a parallel to the famous "Bridges of Königsberg" problem, highlighting that a graph can only have an Eulerian path if there are exactly two vertices of odd degree. Since the layout in this scenario results in three vertices of odd degree, it confirms that an Eulerian path is impossible, thus making the task unsolvable.
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Imagine that the picture shown below is an overhead view of the layout of five rooms in a very strange house. The reason that this house is so strange is that every room has a doorway on every single wall. Your task is to find a continuous path that passes through every doorway exactly once.

http://img258.imageshack.us/img258/5387/3dhouse.th.jpg

The image below is an example of an unsuccessful attempt to solve this problem. The path shown in the diagram passes through every doorway except for one. There is no way to reach the final doorway without passing through one of the doorways twice!

http://img516.imageshack.us/img516/558/exampley.th.jpg

Hint: To make it easier, just copy - paste the image onto paint, erase the previous blue lines, and have fun figuring it out!

P.S. If you do figure this out, please share! I've tried almost every possible way and I still can't figure it out. Thanks!
 
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Well,
suppose there is a path.
Each room with an odd number of doors has to be the start or the end of the path.
But there are 3 rooms like that.
So it is impossible.
:smile:
 
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yup.. tried all ways.. even intersected paths... it is impossible because 1 doorway always remains...
 
Seems similar to the bridges of konigsburg problem. A graph has an Eulerian path iff the there exist precisely two vertices of odd degree. Three vertices of odd degree <=> no Eurlerian path.
 
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