 #1
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Homework Statement:

Hi,
I have included an attachment of the question about differential equations. I found a similar question and solution on this website:
https://doubtnut.com/questionanswer/atangentatapointponthecurvecutsthexaxisataandbisthefootofperpendicularfrompo262330
Relevant Equations:

Given differential equation:
xdy/dx = 2y
Here is my attempt at a solution:
y = f(x)
y_{p}  y_{m} = dy/dx(x_{p}x_{m})
y_{m} = 0
y_{p} = dy/dx(x_{p}x_{m})
x_{m}=y_{p}dy/dx + x_{m}
x_{m} is midpoint of OT
x_{m} = (y_{p}dy/dx + x_{m}) /2
Not sure where to go from there because the solution from the link uses with the midpoint of the points A and B intersecting the xaxis, whereas the assignment question concerns the points M and T on the xaxis, where M is the midpoint between the origin and T. Can anybody give any clues?
y = f(x)
y_{p}  y_{m} = dy/dx(x_{p}x_{m})
y_{m} = 0
y_{p} = dy/dx(x_{p}x_{m})
x_{m}=y_{p}dy/dx + x_{m}
x_{m} is midpoint of OT
x_{m} = (y_{p}dy/dx + x_{m}) /2
Not sure where to go from there because the solution from the link uses with the midpoint of the points A and B intersecting the xaxis, whereas the assignment question concerns the points M and T on the xaxis, where M is the midpoint between the origin and T. Can anybody give any clues?
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