1. dy/dt + f(t)y = 0(adsbygoogle = window.adsbygoogle || []).push({});

2. 1/y.dy = -f(t)dt

3. F(t) = int f(t)dt

4. int 1/y.dy = - int f(t)dt

5. ln|y| = -F(t) + A

I understand up to here, but in my text book the logarithm is eliminated to give:

6. y = A.e^-F(t)

I don't understand how you get from step 5. to step 6. Can someone explain it in the simplest possible way (I get confused sometimes when people use shortcuts to explain things, like writing f instead of f(x)).

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# Solve this differential equation

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