Solve this with lower incomplete gamma function

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SUMMARY

The forum discussion centers on solving the integral \(\int e^{-\frac{2Zr}{a}}*r^{-1}dr\) with boundaries [0,R] using the lower incomplete gamma function. The user attempted to apply the function and derived \(\gamma(0,\frac{2ZR}{a})\), which they identified as infinite. They referenced parameters such as \(Z=81\), \(a\) as the Bohr radius, and \(R=r_0*A^{1/3}\) with \(A=203\) and \(r_0=1.2 \times 10^{-13}\). The discussion highlights that while the integral diverges as \(\epsilon\) approaches 0, it remains finite for \(\epsilon > 0\).

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Homework Statement


\int e^{-\frac{2Zr}{a}}*r^{-1}dr Boundaries:[0,R]




Homework Equations



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The Attempt at a Solution


I tried to solve this with lower incomplete gamma function and got \gamma(0,\frac{2ZR}{a}) which is infinite i think.
Z=81,a:Bohr radius,R=r0*A^(1/3) ,Th:A=203,r0=1,2*10^(-13)
 
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I don't know what the lower incomplete gamma function is, but Mathematica gives me
\int_\epsilon^R \frac{1}{r} e^{-2Zr/a} \, \mathrm dr = \gamma(0, 2Z\epsilon/a) - \gamma(0, 2ZR/a)
which is finite for \epsilon > 0 but diverges for \epsilon \to 0.
 

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